Effective IN() SQL Queries with Spring's JDBCTemplate

You have an IN() query that currently has you building a clause with multiple lines of code:

StringBuilder jobTypeInClauseBuilder = new StringBuilder();
for(int i = 0; i < jobTypes.length; i  ) {
    Type jobType = jobTypes[i];

    if(i != 0) {
        jobTypeInClauseBuilder.append(',');
    }

    jobTypeInClauseBuilder.append(jobType.convert());
}

You seek a more elegant way that is similar to prepared statements' parameter substitution.

Using a Parameter Source

To achieve your desired elegance, you can use a parameter source:

Set ids = ...;

MapSqlParameterSource parameters = new MapSqlParameterSource();
parameters.addValue("ids", ids);

List foo = getJdbcTemplate().query("SELECT * FROM foo WHERE a IN (:ids)",
     parameters, getRowMapper());

NamedParameterJdbcTemplate

Note that this only works if getJdbcTemplate() returns an instance of type NamedParameterJdbcTemplate.