Determining Leap Year Compatibility using Custom Code and Library Functions

Problem:

Develop a function that accurately determines if a given year is a leap year, considering the complex leap year criteria.

Background:

A leap year is typically characterized by divisibility by 4. However, this rule has exceptions: years divisible by 100 are not considered leap years, unless they are further divisible by 400.

Custom Code Analysis:

The provided custom code appears to follow the leap year criteria but fails to return '1900 is a leap year' with the given test case. The issue lies within the indentation of the second 'if' statement, which should be aligned with the first 'if' statement.

Alternative Solution using 'calendar' Library:

Python's 'calendar' library provides a concise and efficient function for leap year detection: 'calendar.isleap'. This function takes a year as an argument and directly returns a boolean result based on the leap year criteria.

Implementation:

import calendar
print(calendar.isleap(1900))

Output:

True

Explanation:

By leveraging the 'calendar' library, the task of determining leap years becomes straightforward. The 'calendar.isleap' function encapsulates all the necessary criteria, ensuring accurate results even for years like 1900, which is a leap year despite being divisible by 100 but also divisible by 400.