How to Resolve "General error: 2006 MySQL server has gone away" While Inserting Records
Introduction:
Inserting data into a MySQL database can occasionally result in the error "General error: 2006 MySQL server has gone away." This error occurs when the connection to the server is lost, typically due to one of two variables in the MySQL configuration.
Solution:
The key to resolving this error is to adjust the wait_timeout and interactive_timeout variables. These variables control the maximum time that MySQL will wait before terminating an inactive connection.
Adjusting Timeout Variables:
Example in PHP:
<?php
$db = new db();
$results = $db->query("SHOW VARIABLES LIKE '%timeout%'", TRUE);
echo "<pre>";
var_dump($results);
echo "</pre>";
$results = $db->query("SET session wait_timeout=28800", FALSE);
// UPDATE - this is also needed
$results = $db->query("SET session interactive_timeout=28800", FALSE);
$results = $db->query("SHOW VARIABLES LIKE '%timeout%'", TRUE);
echo "<pre>";
var_dump($results);
echo "</pre>";
class db {
public $mysqli;
public function __construct() {
$this->mysqli = new mysqli(DB_SERVER, DB_USER, DB_PASS, DB_NAME);
if (mysqli_connect_errno()) {
exit();
}
}
public function __destruct() {
$this->disconnect();
unset($this->mysqli);
}
public function disconnect() {
$this->mysqli->close();
}
function query($q, $resultset) {
/* create a prepared statement */
if (!($stmt = $this->mysqli->prepare($q))) {
echo("Sql Error: " . $q . ' Sql error #: ' . $this->mysqli->errno . ' - ' . $this->mysqli->error);
return false;
}
/* execute query */
$stmt->execute();
if ($stmt->errno) {
echo("Sql Error: " . $q . ' Sql error #: ' . $stmt->errno . ' - ' . $stmt->error);
return false;
}
if ($resultset) {
$result = $stmt->get_result();
for ($set = array(); $row = $result->fetch_assoc();) {
$set[] = $row;
}
$stmt->close();
return $set;
}
}
}
Additional Considerations:
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