"If a worker wants to do his job well, he must first sharpen his tools." - Confucius, "The Analects of Confucius. Lu Linggong"
Front page > Programming > How Can You Access a Variable\'s Value Using its Name as a String in C++?

How Can You Access a Variable\'s Value Using its Name as a String in C++?

Published on 2024-11-27
Browse:775

How Can You Access a Variable\'s Value Using its Name as a String in C  ?

Accessing Variable Value from String Representing Variable Name in C

In C , it is possible to obtain the value of a variable dynamically using its name as a string. This technique, commonly known as reflection, allows for flexible debugging and introspection capabilities.

To achieve this, you can utilize the following steps:

  1. Obtain Variable Address:

    • Employ the "&" operator to retrieve the address of the variable. For example, &counter returns the memory location where counter is stored.
  2. Cast to Pointer:

    • Cast the variable address to a pointer of the variable's type. This allows you to access the variable's value indirectly. For example: int* counterPtr = static_cast(&counter);
  3. Access Value via Pointer:

    • Use the dereference operator (*) to access the variable's value through the pointer. For example: std::cout
  4. Function Wrapper:

    • To make the process more convenient, you can create a function that takes a string representing the variable name and returns the variable's value. This function simplifies the steps outlined above:

      template 
      T valueOf(const std::string& varName) {
        T* varPtr = static_cast(std::addressof(varName));
        return *varPtr;
      }

Usage:

With the valueOf function, you can obtain variable values dynamically:

std::cout ("counter") 
Latest tutorial More>

Disclaimer: All resources provided are partly from the Internet. If there is any infringement of your copyright or other rights and interests, please explain the detailed reasons and provide proof of copyright or rights and interests and then send it to the email: [email protected] We will handle it for you as soon as possible.

Copyright© 2022 湘ICP备2022001581号-3